2=-8r^2-8r

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Solution for 2=-8r^2-8r equation: 



2=-8r^2-8r

We move all terms to the left:

2-(-8r^2-8r)=0

We get rid of parentheses

8r^2+8r+2=0

a = 8; b = 8; c = +2;
Δ = b2-4ac
Δ = 82-4·8·2
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{-8}{16}=-1/2$

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